Question

Vertex of the parabola $x^2+4x+2y-7=0$ is

• A. $(-2,\frac{11}{2})$
• B. $(-2,2)$
• C. $(-2,11)$
• D. $(2,11)$

Answer 1

The correct option is A $(-2,\frac{11}{2})$

$(x+2{)}^2=-2y+7+4\Rightarrow (x+2{)}^2=-2(y-\frac{11}{2})$
Hence vertex is $(-2,\frac{11}{2})$.