Vertex of the parabola $x^{2} + 4 x + 2 y - 7 = 0$ is

(- 2, 11 / 2)

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(- 2, 2)

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(- 2, 11)

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(2, 11)

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Solution

The correct option is A $(- 2, 11 / 2)$
$x^{2} + 4 x + 2 y - 7 = 0$
$x^{2} + 4 x + 4 - 4 + 2 y - 7 = 0$
$(x + 2)^{2}$ = -2y+11
$(x + 2)^{2} = - 2 (y \frac{- 11}{2})$
vertex of this parabola is $(- 2, \frac{11}{2})$

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x^{2} + 4 x + 2 y - 7 = 0

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A

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