Question

Vertices of a $△$ABC are A (2, 2), B (-4, -4)and C (5, -8), then the length of the median through C is :

• A. $\sqrt{65}$
• B. $\sqrt{117}$
• C. $\sqrt{85}$
• D. $\sqrt{113}$

Answer 1

The correct option is C $\sqrt{85}$

A median of a triangle is a line segment that joins the vertex of a triangle to
the midpoint of the opposite side.
Mid point of two points ${(x}_1,y_1)$ and ${(x}_2,y_2)$ is calculated by the formula $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$
Using this formula,
mid point of AB $=D=(\frac{2-4}{2},\frac{2-4}{2})=(-1,-1)$

Distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ can be calculated using the formula $\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

Distance between the points A $(5,-8)$ and D $(-1,-1)=\sqrt{{(-1-5)}^2+{(-1+8)}^2}=\sqrt{36+49}=\sqrt{85}$