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Vertices of a...

Question

Vertices of a parallelogram $A B C D$ are $A (3, 1), B (13, 6), C (3, 16)$ . If a line passing trough the origin divides the parallelogram into two congruent parts then the slope of the line is

A

\frac{11}{12}

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B

\frac{11}{8}

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C

\frac{25}{8}

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D

\frac{13}{8}

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Solution

The correct option is B $\frac{11}{8}$

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