Question

Very-Short-Answer Questions

Show that x = −2 is a solution of $3x^2+13x+14=0$. [CBSE 2008]

Answer 1

The given equation is $3x^2+13x+14=0$.

Putting x = −2 in the given equation, we get

LHS = $3\times {\left(-2\right)}^2+13\times \left(-2\right)+14=12-26+14=0$ = RHS

∴ x = −2 is a solution of the given equation.