Question

Simplify: $2\frac{2}{3}+3\frac{1}{2}$

Answer 1

Given: $2\frac{2}{3}+3\frac{1}{2}$

$=\frac{3\times 2+2}{3}+\frac{2\times 3+1}{2}$

$=\frac{8}{3}+\frac{7}{2}$

Now, LCM of $3$ and $2$ is $6$ as they are co prime numbers.

Therefore,

$=\frac{8}{3}\times \frac{2}{2}+\frac{7}{2}\times \frac{3}{3}$

$=\frac{16}{6}+\frac{21}{6}$

$=\frac{16+21}{6}$

$=\frac{37}{6}$

$=6\frac{1}{6}$

$\therefore 2\frac{2}{3}+3\frac{1}{2}=6\frac{1}{6}$