Question 81 (vi)
Add:
3a(a - b + c) , 2b(a - b + c)
3a(a - b + c) + 2b(a - b + c)
= 3a2−3ab+3ac+2ab−2b2+2bc
= 3a2−2b2−ab+2bc+3ac
Question 5(d) Substract: 3a(a+b+c)−2b(a−b+c)from 4c(−a+b+c).