Question 85 (vi)
Expand the following, using suitable identities.
(x+3)(x+7)
We have, (x+3)(x+7)=x2+(3+7)x+3×7 [using the identity, (x+a)(x+b)=x2+(a+b)x+ab] =x2+10x+21
Question 85 (iv)
(23x−32y)2
Question 85 (vii)
(2x+9)(2x−7)
Question 85 (xiv)
(7x+5)2
Question 85 (x)
(2x−5y)(2x−5y)