Find the value of:
−712÷(−213)
Given:−712÷(−213)=−712×13(−2)=(−7)×1312×(−2)=−91−24=31924
(i) (−4)÷23
(ii) −35÷2
(iii) −45÷−3
(iv) −18÷34
(v) −213÷17
(vi) −712÷−213
(vii) 313÷−465
Question 4 (v)
Find the value of: −213÷17
Re-arrange suitably and find the sum in each of the following :
(i)1112+−173+112+−252
(ii)−67+−56+−49+−157
(iii)35+73+95+−1315+−73
(iv) 413+−58+−813+913
(v)23+−45+13+25
(vi) 18+512+27+712+97+−516