Question 1 - - Multiply the binomials-3-4 a2-3 b2 and 4a2-2-3 b2

( 3/4a^2+3b^2 )× 4 ( a^2 2/3 b^2 )= ( 3/4a^2+3b^2 )× ( 4a^2 8/3 b^2 ) 3/4a^2× ( 4a^2 8/3 b^2 )+3b^2× ( 4a^2 8/3 b^2 ) 3/4a^2×4a^2 3/4a^2×8/3b^2+3b^2×4a^2 3b^ ...

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Byju's Answer

Standard VI

Mathematics

Addition of Unlike Terms

Question 1 𝐯...

Question

Question 1(vi)
Multiply the binomials:
$(\frac{3}{4} a^{2} + 3 b^{2}) a n d 4 (a^{2} - \frac{2}{3} b^{2})$

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Solution

$(\frac{3}{4} a^{2} + 3 b^{2}) \times 4 (a^{2} - \frac{2}{3} b^{2}) = (\frac{3}{4} a^{2} + 3 b^{2}) \times (4 a^{2} - \frac{8}{3} b^{2})$
$\frac{3}{4} a^{2} \times (4 a^{2} - \frac{8}{3} b^{2}) + 3 b^{2} \times (4 a^{2} - \frac{8}{3} b^{2})$
$\frac{3}{4} a^{2} \times 4 a^{2} - \frac{3}{4} a^{2} \times \frac{8}{3} b^{2} + 3 b^{2} \times 4 a^{2} - 3 b^{2} \times \frac{8}{3} b^{2}$
$= 3 a^{4} - 2 a^{2} b^{2} + 12 a^{2} b^{2} - 8 b^{4}$
$= 3 a^{4} + 10 a^{2} b^{2} - 8 b^{4}$

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Similar questions

Q. Multiply the binomials

(\frac{3}{4} a^{2} + 3 b^{2})

and

4 (a^{2} - \frac{2}{3} b^{2})

Question 1(vi)
Multiply the binomials:
$(\frac{3}{4} a^{2} + 3 b^{2}) a n d 4 (a^{2} - \frac{2}{3} b^{2})$

Q. Multiple the binomials.

(\frac{3}{4} a^{2} + 3 b^{2})

and

4 (a^{2} - \frac{2}{3} b^{2})

Q. Multiply the binomials.

(\frac{3}{4} a^{2} + 3 b^{2})

and

4 (a^{2} - \frac{2}{3} b^{2})

Q. Solve:

[\frac{3}{4} a^{2} + 3 b^{2}] \times [4 (a^{2} - \frac{2}{3} b^{2})]

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Addition of Unlike Terms

Standard VI Mathematics

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Question 1(vi) Multiply the binomials: (34a2+3b2)and 4(a2−23b2)

(34a2+3b2)×4(a2−23b2)=(34a2+3b2)×(4a2−83b2) 34a2×(4a2−83b2)+3b2×(4a2−83b2) 34a2×4a2−34a2×83b2+3b2×4a2−3b2×83b2 =3a4−2a2b2+12a2b2−8b4 =3a4+10a2b2−8b4

Question 1(vi)
Multiply the binomials:
$(\frac{3}{4} a^{2} + 3 b^{2}) a n d 4 (a^{2} - \frac{2}{3} b^{2})$