Question 83 (vi)
Multiply the following :
abc, (bc + ca)
We have, abc and (bc + ca) ∴abc×(bc+ca)=abc×bc+abc×ca=ab2c2+a2bc2
Question 83 (iv)
−5a2bc,11ab,13abc2
Question 83 (iii)
15xy2,17yz2
Question 83 (ii)
3x2y2z2,17xyz