Question 3 (vi)
Subtract:
−x2+10x−5 from 5x−10
5x−10−(−x2+10x−5)=5x−10+x2−10x+5 =x2+5x−10x−10+5=x2−5x−5
(-10 x -10 x -10 x -10 x -10 x -10 x -10 x -10) divided by (-5 x -5 x -5 x -5 x -5) gives
Question 6 (b)
From the sum of 4+3x and 5−4x+2x2, subtract the sum of 3x2−5x and −x2+2x+5.