Question 1 vi Without actually performing the long division- state whether 23-23- 52 will have a terminating decimal expansion or a non-terminating repeating decimal expansion-

Name: NCERT - Grade 10 - Mathematics - Real Numbers - Q16_6
Uploaded: 2022-07-04T10:36:42+05:30
Description: 23/2^3 × 5^2 The denominator is in the form of 2^m× 5^n, where m = 3 and n = 2. Thus, the rational number 23/2^3 × 5^2 has a terminating decimal expansion. ...

23/2^3 × 5^2 The denominator is in the form of 2^m× 5^n, where m = 3 and n = 2. Thus, the rational number 23/2^3 × 5^2 has a terminating decimal expansion. ...

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Standard VII

Mathematics

Writing Rational Numbers as Decimals

Question 1 vi...

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Question 1 (vi)
Without actually performing the long division, state whether $\frac{23}{2^{3} \times 5^{2}}$ will have a terminating decimal expansion or a non-terminating repeating decimal expansion.

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Solution

$\frac{23}{2^{3} \times 5^{2}}$
The denominator is in the form of $2^{m} \times 5^{n}$ , where m = 3 and n = 2.
Thus, the rational number $\frac{23}{2^{3} \times 5^{2}}$ has a terminating decimal expansion.

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Question 1 (vi) Without actually performing the long division, state whether 2323× 52 will have a terminating decimal expansion or a non-terminating repeating decimal expansion.

2323× 52 The denominator is in the form of 2m×5n, where m = 3 and n = 2. Thus, the rational number 2323× 52 has a terminating decimal expansion.

Question 1 (vi)
Without actually performing the long division, state whether $\frac{23}{2^{3} \times 5^{2}}$ will have a terminating decimal expansion or a non-terminating repeating decimal expansion.

$\frac{23}{2^{3} \times 5^{2}}$
The denominator is in the form of $2^{m} \times 5^{n}$ , where m = 3 and n = 2.
Thus, the rational number $\frac{23}{2^{3} \times 5^{2}}$ has a terminating decimal expansion.