Given:
The length of the wrench in the first case, l1=45 cm
The force/effort applied in the first case, F1=220 N
The moment of force generated in this turning effect of opening the nut using a wrench will be the product of the force applied and the length of the wrench used.
i.e. in the first case, the moment of force, τ1=F1×l1
=220 N×45 cm
=9900 N-cm or 99 N-m−−−−−−(1)
For the same moment of force, if the length of the wrench is reduced, the force/effort needed to open the nut, will be more.
So, when a wrench of length 0.3 m is used instead, the new force needed will be:
99 N-m=Fnew×0.3 m
⟹Fnew=99 N-m0.3 m=9903=330 N
Therefore, the effort needed in the shorter wrench case is more and is equal to 330 N.