Question

Find the sum:

$-2\frac{1}{3}+4\frac{3}{5}$

Answer 1

We have, $-2\frac{1}{3}+4\frac{3}{5}$

$=\frac{-7}{3}+\frac{23}{5}$ [$\because a\frac{b}{c}=\frac{(a\times c)+b}{c}$]

$=\frac{-7\times 5}{3\times 5}+\frac{23\times 3}{5\times 3}$

$=\frac{-35}{15}+\frac{69}{15}$ [L.C.M of $3$ and $5$ is $15$]

$=\frac{-35+69}{15}$

$=\frac{34}{15}$

$=2\frac{4}{15}$