(viii) -10, -13, -16, -19, ...

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Solution

(viii) In the given sequence, we have:
t₁ = –10, t₂ = –13, t₃ = –16 and t₄ = –19
Thus, we have:
t₂ – t₁ = –13 + 10 = –3
t₃ – t₂ = –16 + 13 = –3
t₄ – t₃ = –19 + 16 = –3
Because the difference between any two consecutive terms is constant, which is –3, the given sequence is an arithmetic progression with common difference –3.

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