(viii) In the given sequence, we have:
t1 = –25, t2 = –23, t3 = –21 and t4 = –19
Thus, we get:
t1 = –25
t2 = –23 = –25 + 2 = t1 + 2 = t(2 – 1) + 2
t3 = –21 = –23 + 2 = t2 + 2 = t(3 – 1) + 2
t4 = –19 = –21 + 2 = t3 + 2 = t(4 – 1) + 2
We have:
tn = t(n – 1) + 2
Now, to find the next four terms, we need to take n = 5, 6, 7 and 8.
Here,
t5 = t(5 – 1) + 2 = t4 + 2 = –19 + 2 = –17
t6 = t(6 – 1) + 2 = t5 + 2 = –17 + 2 = –15
t7 = t(7 – 1) + 2 = t6 + 2 = –15 + 2 = –13
t8 = t(8 – 1) + 2 = t7 + 2 = –13 + 2 = –11
Thus, the next four terms are –17, –15, –13 and –11.