Question

Question 2(viii)
Factorise the following expressions
$-4a^2+4ab-4ca$

Answer 1

$4a^2=2\times 2\times a\times a4ab=2\times 2\times a\times b4ca=2\times 2\times c\times aThecommonfactorsare2,2anda\therefore -4a^2+4ab-4ca=-(2\times 2\times a\times a)+(2\times 2\times a\times b)-(2\times 2\times c\times a)=2\times 2\times a[-(a)+b-c]=4a(-a+b-c)$