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Byju's Answer
Standard VIII
Mathematics
Factorisation by Common Factors
Question 2vii...
Question
Question 2(viii)
Factorise the following expressions
−
4
a
2
+
4
a
b
−
4
c
a
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Solution
4
a
2
=
2
×
2
×
a
×
a
4
a
b
=
2
×
2
×
a
×
b
4
c
a
=
2
×
2
×
c
×
a
T
h
e
c
o
m
m
o
n
f
a
c
t
o
r
s
a
r
e
2
,
2
a
n
d
a
∴
−
4
a
2
+
4
a
b
−
4
c
a
=
−
(
2
×
2
×
a
×
a
)
+
(
2
×
2
×
a
×
b
)
−
(
2
×
2
×
c
×
a
)
=
2
×
2
×
a
[
−
(
a
)
+
b
−
c
]
=
4
a
(
−
a
+
b
−
c
)
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using identity
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Factorisation by Common Factors
Standard VIII Mathematics
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