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Question

Question 2(viii)
Factorise the following expressions
4a2+4ab4ca

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Solution

4a2=2×2×a×a4ab=2×2×a×b4ca=2×2×c×aThe common factors are 2,2 and a4a2+4ab4ca=(2×2×a×a)+(2×2×a×b)(2×2×c×a)=2×2×a[(a)+bc]=4a(a+bc)

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