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Question

Question 89 (viii)

Factorise the following, using the identity, a2+2ab+b2=(a+b)2

a2x2+2abxy+b2y2


Solution

We have, a2x2+2abxy+b2y2
=(ax)2+2.ax.by+(by)2=(ax+by)2=(ax+by)(ax+by)

Mathematics
NCERT Exemplar
Standard VIII

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