Question 89 (viii)

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$

$a^{2} x^{2} + 2 a b x y + b^{2} y^{2}$

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Solution

We have, $a^{2} x^{2} + 2 a b x y + b^{2} y^{2}$
$= (a x)^{2} + 2. a x . b y + (b y)^{2} = (a x + b y)^{2} = (a x + b y) (a x + b y)$

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