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Trigonometric Identity- 2

Question 5 vi...

Question

Question 5 (viii)
Prove the following identities, where the angles involved are acute angles for which the expressions are defined.
(viii) $(s i n A + c o s e c A)^{2} + (c o s A + s e c A)^{2} = 7 + t a n^{2} A + c o t^{2} A$

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Solution

(viii) $(s i n A + c o s e c A)^{2} + (c o s A + s e c A)^{2} = 7 + t a n^{2} A + c o t^{2} A L . H . S = (s i n A + c o s e c A)^{2} + (c o s A + s e c A)^{2} = (s i n^{2} A + c o s e c^{2} A + 2 s i n A c o s e c A) + (c o s^{2} A + s e c^{2} A + 2 c o s A s e c A) = (s i n^{2} A + c o s^{2} A) + 2 s i n A (\frac{1}{s i n A}) + 2 c o s A (\frac{1}{c o s A}) + 1 + t a n^{2} A + 1 + c o t^{2} A = 1 + 2 + 2 + 2 + t a n^{2} A + c o t^{2} A = 7 + t a n^{2} A + c o t^{2} A = R . H . S$

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Similar questions

Q. Prove the following identity, where the angles involved are acute angles for which the expression is defined.

(s i n A + c o s e c A)^{2} + (c o s A + s e c A)^{2} = 7 + t a n^{2} A + c o t^{2} A

Question 5 (x)
Prove the following identities, where the angles involved are acute angles for which the expressions are defined.
$(\frac{1 + t a n^{2} A}{1 + c o t^{2} A}) = (\frac{1 - t a n A}{1 - c o t A})^{2} = t a n^{2} A$

Q. Prove the following identities, where the angles involved are acute angles for which the expressions are defined.

\frac{cos A}{1 + sin A} + \frac{1 + sin A}{cos A} = 2 sec A

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Q. Question 5 (ii)
Prove the following identities, where the angles involved are acute angles for which the expressions are defined.
(ii)

\frac{c o s A}{(1 + s i n A)} + \frac{(1 + s i n A)}{c o s A} = 2 s e c A

(s i n A + c o s e c A)^{2} + (c o s A + s e c A)^{2} = 7 + t a n^{2} A + c o t^{2} A

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Trigonometric Identity- 2

Standard X Mathematics

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