Question 86 (viii)
Using suitable identities, evaluate the following:
52×53
We have, 52×53=(50+2)(50+3)=(50)2+(2+3)50+2×3 [using the identity, (x+a)(x+b)=x2+(a+b)x+ab] =2500+250+6=2756
Question 86 (vii)
47×53
Question 86 (i)
(52)2