Question

(viii) $\frac{x}{2}+3y=11;x+5y=20$

Answer 1

$$\begin{gathered} \frac{x}{2}+3y=11 \\ \Rightarrow x+6y=22...\left(\mathrm{i}\right) \\ x+5y=20....\left(\mathrm{ii}\right) \\ \mathrm{Subtracting}\mathrm{eq}\left(\mathrm{ii}\right)\mathrm{from}\left(\text{i}\right),\text{we get:} \\ x+6y=22 \\ x+5y=20 \\ \underline{---} \\ y=2 \\ \therefore y=2 \\ \mathrm{Substituting}y=2\mathrm{in}\left(\mathrm{i}\right),\mathrm{we}\mathrm{get}: \\ \Rightarrow x+6\times 2=22 \\ \Rightarrow x=22-12 \\ \therefore x=10 \\ \mathrm{Hence},x=10,y=2\mathrm{is}\mathrm{the}\mathrm{solution}\mathrm{of}\mathrm{the}\mathrm{given}\mathrm{equations}. \end{gathered}$$