Question

Vijay had some bananas , and he divided them into two lots A and B . He sold first lot at the rate of ₹2 for 3 bananas and the second lot at the rate of ₹1 per banana and got a total of ₹400 . If he had sold the first lot at the rate of ₹1 per banana and the second lot at the rate of ₹4 per five bananas, his total collection would have been ₹460 . Find the total number of bananas he had .

Answer 1

Let the bananas in lot A be x and that in lot B be y.
Vijay sold 3 bananas for Rs 2 in lot A.
So, the cost of x bananas in lot A = $\frac{2}{3}x$
Now,
Cost of x bananas in lot A + Cost of y bananas in lot B = ₹400
$\therefore \frac{2}{3}x+y=400$
⇒ 2x + 3y = 1200 .....(i)
Now, if he sells the first lot at the rate of Rs 1 per banana and second for Rs 4 for 5 bananas, then
$x+\frac{4}{5}y$ = ₹460
⇒ 5x + 4y = 2300 .....(ii)
Solving (i) and (ii), we get
x = 300 and y = 200
So, the total number of bananas = x + y = 300 + 200 = 500.