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Question

Vijay invests some amount in 'National saving certificate'. For the 1st year he invests Rs. 500, for the 2nd year he invests Rs. 700, for the 3rd year he invests Rs. 900, and so on. How much amount he has invested in 12 years?

A
18600
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B
19200
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C
15400
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D
15600
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Solution

The correct option is B 19200
The investment done by vijay in each year is as follows 500,700,900........
This sequence makes an AP with first term a=500, common difference d=200
Given, number of terms n=12
Since,
Sn=n2[2a+(n1)d]
S12=122[2×500+(121)200]
S12=6[1000+2200]
S12=19200

vijay's total investment in 12 years S12=19200

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