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Question

Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in the opposite direction. The block moves a distance of 6.5 m in the same direction in which Vijay is pulling it. Calculate work done on the block.

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Solution

Given:
Force applied by Vijay, F1=22 N
Force applied by Gopal, F2=10 N.
Displacement, s=6.5 m

Since, both the forces are acting in the opposite directions, net force is given by:
F=F1F2
F=2210=12 N

The work done on the block is given by the product of displacement and the net force applied on it. Hence it is given by:
W=F×s
W=12×6.5=78 J

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