Vikram travels 4 m east, take a right turn and again travels for 3 m. How far is he from the starting point?
5 m
AC is the required distance, which can be found using Pythagoras' theorem as follows:
AC2=AB2+BC2 AC2=42+32⇒AC2=16+9⇒AC2=25⇒AC=5 m
Thus, Vikram is 5 m away from his starting point.