Vineet wrote a sequence of numbers in which every odd number is 7 less than the previous number, and every even number is 2 more than the previous one. The first term of the sequence is 100. Find the 5th term. [4 MARKS]
Steps: 3 Marks
Answer: 1 Mark
Given that:
The first term of the sequence = 100.
Now every odd number is 7 less than the previous one and every even number is 2 more than the previous one.
So the second term=100 + 2 = 102
Third term = 102 - 7 = 95
Fourth term = 95 + 2 = 97
Fifth term = 97 - 7 = 90
Hence, the fifth term of the sequence is 90.