Visible light passing through a circular hole forms a diffraction disc of radius 0.1 mm on a screen. If X-ray is passed through the same set up, the radius of the diffraction disc will be
A
zero
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B
< 0.1 mm
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C
0.1 mm
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D
> 0.1 mm
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Solution
The correct option is B < 0.1 mm r∝λ λX−ray<λvisiblelight hence the radius of diffraction disc formed will be smaller.