Vitamin C $(M = 176)$ is a compound of $C, H, O$ found in many natural sources, especially citrus fruits. When a $1.0 g$ sample of vitamin C is placed in a combustion chamber and burned, the following data is obtained.
$Mass of C O_{2} absorber after combustion = 83.85 g$
$Mass of C O_{2} absorber before combustion = 82.35 g$
$Mass of H_{2} O absorber after combustion = 37.96 g$
$Mass of H_{2} O absorber before combustion = 37.55 g$
What is the percentage of carbon by weight in vitamin C?

66.7 %

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40.9 %

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20 %

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60 %

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Solution

The correct option is B $40.9 %$
Mass of $C O_{2}$ produced = $83.85 - 82.35 = 1.5 g$
$∴ Percentage of C = \frac{12}{44} \times \frac{1.5}{1.0} \times 100 = 40.9 %$

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Similar questions

(M = 176)

C, H, O

1.0 g

Mass of C O_{2} absorber after combustion = 83.85 g

Mass of C O_{2} absorber before combustion = 82.35 g

Mass of H_{2} O absorber after combustion = 37.96 g

Mass of H_{2} O absorber before combustion = 37.55 g

Vitamin C is also known as ascorbic acid. Citrus fruits are a good source of this vitamin.

Which of the following fruits is a good source of vitamin C?

Vitamin C is essential for keeping the body disease-free. It is obtained from citrus fruits.

The disease caused by the deficiency of vitamin C in the body is

C, H, O

C O_{2}

H_{2} O

C, H

O

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