void fun (int n)
{
if (n>0)
{
printf("CSE");
fun( n - 1);
}
printf("2020");
printf("2020);
}
The output of the above program when fun(n) is called for some positive integer n
A
n times "CSE" followed by 2(n+1) times "2020"
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B
n times "CSE" followed by 2n times "2020" alternatively one after another
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C
2n+1 times "2020" followed by n times "CSE"
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D
n times "CSE" followed by 2n times "2020"
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Solution
The correct option is A n times "CSE" followed by 2(n+1) times "2020" (D)
The fun(n) prints n times "CSE" followed by 2n +2 times "2020"