wiz-icon
MyQuestionIcon
MyQuestionIcon
9
You visited us 9 times! Enjoying our articles? Unlock Full Access!
Question

Volatile liquids A and B have volumes of 100 mL and 40 mL respectively at a given temperature . They are mixed to form a solution which has volume of 125 mL.
Choose the correct option:

A
It is an ideal mixture
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Mixture boils at a temperature higher than the boiling point of its components
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Mixture boils at a temperature lower than the boiling point of its components
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Mixture boils at a temperature as same as the boiling point of its components
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Mixture boils at a temperature higher than the boiling point of its components
Volume of 'A' = 100 mL
Volume of 'B' = 40 mL
For ideal condition,
Volume of solution of A + B =140 mL
Original volume of solution =125 mL
Thus, the given solution is a non-ideal solution which does not obey Raoult's law.

Here,
ΔVmix=125140=15<0
This condition occurs whe solvent-solute interaction is more than the solvent-solvent and the solute-solute interactions.
Thus, the total vapour pressure of the solution will be less than the ideal vapour pressure.
PT<XA.pA+XB.pB

Hence, a non-ideal solution showing large negative deviation from Raoult’s law and solution mixture boils at a temperature higher than the boiling point of it components.
Thus, it is a maximum boiling azeotrope.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ideal and Non Ideal Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon