Question

Voltage applied between cathode and anode of an X-ray tube is 18 kV. Calculate the minimum wavelength of the X-rays produced.

Answer 1

Given $V=18kV=18\times {10}^{3}V$
${\lambda }_{min}=\frac{hc}{eV}$
$=\frac{6.6\times {10}^{-34}\times 3\times {10}^8}{1.6\times {10}^{-19}\times 18\times {10}^3}$
$=6.88\times {10}^{-11}m$.