Question

Voltage of an AC source is given by V= 200sin$\left(100\pi t\right).cos\left(100\pi t\right)$ where t is in seconds and V is in volts. Then the peak voltage is
volts.

• A. 50
• B. 100
• C. 200
• D. 400

Answer 1

The correct option is B 100

$V=100\times 2sin100\pi tcos100\pi t=100sin200\pi t$
$\Rightarrow V_0=100$ Volts and Frequency =100Hz