Voltmeters $V_{1}$ and $V_{2}$ are connected in series across a D.C. line. $V_{1}$ reads 80 volt and has a per volt resistance of 200 ohm. $V_{2}$ has a total resistance of 32 kilo ohm. The line voltage is

120 Volt

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160 Volt

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220 Volt

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240 Volt.

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Solution

The correct option is D 240 Volt.
$V_{1} = 80 V$
Total of resistance of $n = 80 \times 200 ω$
$= 16 k ω$
resistance of $V_{2} = 32 k ω$
$i = \frac{V_{1}}{r_{1}} = \frac{V_{2}}{r_{2}}$
$V_{2} = \frac{V_{1}}{r_{1}} r_{2}$
$V_{2} = \frac{80 \times 32}{16}$
$V_{2} = 160 v o l t s$
line voltage $= V_{1} + V_{2}$
$= 160 + 80$

$= 240 V$

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