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Question

Volume at NTP of oxygen required to completely burn 1 kg of coal (100% carbon):

A
22.400 L
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B
22.4×103L
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C
1.86×103L
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D
1000 L
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Solution

The correct option is C 1.86×103L
At NTP conditions, 1 mole of a gas occupies 22.4 L of volume. So, for combustion of 1 kg of coal

number of mole of coal=100012=83.333moles we will require 83.333moles of oxygen (O2) which is occupies =83.333×22.4

=1.866×103 L of volume of NTP.

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