Question

Volume at NTP of oxygen required to completely burn $1kg$ of coal ($100$ % carbon) is:

• A. $22.4L$
• B. $22.4\times {10}^{3}L$
• C. $1.86\times {10}^{3}L$
• D. $1000L$

Answer 1

The correct option is C $1.86\times {10}^{3}L$

Mass of $C=1000g$

Moles of $C=\frac{1000}{12}=83.34moles$

$C+O_2⟶C{O}_2$

$1$ moles $C$ requires $1$ mole $O_2$ to burn.

So, $83.34$ mole $C$ requires $83.34$ moles $O_2$

At NTP, $1$ mole gas occupies $22.4litres$.

So, $83.34moles$ occupies $83.34\times 22.4=1.86\times {10}^{3}L$

Hence, option $C$ is correct.