Volume enclosed between a cylindrical vessel consisting of 2 concentric cylinders- is 90- m-3- If outer radius is 5m and height of the cylinder is 10m- Find the thickness of the cylindrical vessel-1m-1-5m-2m-2-5m-

The correct option is A 1m Let outer radius =R and inner radius = r ⇒π (R^2 r^2)h = volume enclosed between the cylinders π (25 r^2)10 = 90 π ⇒ r =4 ...

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Standard VIII

Mathematics

Volume of combined figures

Volume enclos...

Question

Volume enclosed between a cylindrical vessel consisting of 2 concentric cylinders is 90 $π$ $m^{3}$ . If outer radius is 5m and height of the cylinder is 10m. Find the thickness of the cylindrical vessel.

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Solution

The correct option is A
1m

Let outer radius =R and inner radius = r

$\Rightarrow π (R^{2} - r^{2}) h$ = volume enclosed between the cylinders

$π (25 - r^{2}) 10 = 90 π$

$\Rightarrow r = 4 m$

Thickness $= R - r = 1 m$

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Volume enclosed between a cylindrical vessel consisting of 2 concentric cylinders is 90π m3. If outer radius is 5m and height of the cylinder is 10m. Find the thickness of the cylindrical vessel.

The correct option is A 1m Let outer radius =R and inner radius = r ⇒π(R2−r2)h = volume enclosed between the cylinders π(25−r2)10=90π ⇒r=4 m Thickness =R−r=1 m

Volume enclosed between a cylindrical vessel consisting of 2 concentric cylinders is 90 $π$ $m^{3}$ . If outer radius is 5m and height of the cylinder is 10m. Find the thickness of the cylindrical vessel.

The correct option is A
1m

Let outer radius =R and inner radius = r

$\Rightarrow π (R^{2} - r^{2}) h$ = volume enclosed between the cylinders

$π (25 - r^{2}) 10 = 90 π$

$\Rightarrow r = 4 m$

Thickness $= R - r = 1 m$