Volume occupied by 1 gram of oxygen at STP is

0.7L

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2.4 L

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2.24 L

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5.2 L

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Solution

The correct option is A
0.7L

$V$ at S.T.P. = $\frac{W}{G M W} \times 22.4 l$

$V = \frac{1}{32} \times 22.4 = 0.7 L$

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