Volume occupied by a mixture of 2 grams of hydrogen and 32 grams of oxgen at STP is:

11.2 litres

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22.4 litres

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33.6 litres

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44. 8 litres

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Solution

The correct option is D 44. 8 litres
No. of moles of H2 = 1 and volume occupied at STP = 22.4litres
No. of moles of oxygen gas = 1 and volume occupied at STP = 22.4 litres
Thus, total volume occupied by two gases =44.8 litres.

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