Question

Volume occupied by one molecule of water is:

[density $=1{gcm}^{-3}]$

• A. $3.0\times {10}^{-23}{cm}^3$
• B. $5.5\times {10}^{-23}{cm}^3$
• C. $9\times {10}^{-23}{cm}^3$
• D. $6.023\times {10}^{-23}{cm}^3$

Answer 1

The correct option is A $3.0\times {10}^{-23}{cm}^3$

$1c{m}^3=1gm$ of $H_{2}O=\frac{1}{18}mol$ of $H_{2}O$

$=\frac{1}{18}\times 6\times {10}^{23}$ molecules of $H_{2}O$

$\Rightarrow 1c{m}^3$ has $\frac{1}{3}\times {10}^{23}$ molecules of $H_{2}O$

$\therefore$ Volume of 1 molecule of $H_{2}O=\frac{1}{\frac{1}{3}\times {10}^{23}}c{m}^3$

$=3\times {10}^{-23}c{m}^3$

Hence, the correct option is $A$