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Question

Volume of $0.50 M$ $N a O H$ solution required to react with $40.0$ mL of $0.05$ M $H_{2} S O_{4}$ solution is :

40.0

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80.0

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20.0

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8.0

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Solution

The correct option is D $8.0$ mL
Sulfuric acid is a dibasic acid.

The expression is as follows:
$M_{1} V_{1} = 2 M_{2} V_{2}$
Where, 1 represents for $N a O H$ and 2 represents for $H_{2} S O_{4}$

$0.50 \times V_{1} = 2 \times 40.0 \times 0.05$

$V_{1} = 8.0$ mL

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Volume of 0.50 M NaOH solution required to react with 40.0 mL of 0.05 M H2SO4 solution is :

The correct option is D 8.0 mLSulfuric acid is a dibasic acid.The expression is as follows:M1V1=2M2V2Where, 1 represents for NaOH and 2 represents for H2SO40.50×V1=2×40.0×0.05V1=8.0 mL

Volume of $0.50 M$ $N a O H$ solution required to react with $40.0$ mL of $0.05$ M $H_{2} S O_{4}$ solution is :

The correct option is D $8.0$ mL
Sulfuric acid is a dibasic acid.

The expression is as follows:
$M_{1} V_{1} = 2 M_{2} V_{2}$
Where, 1 represents for $N a O H$ and 2 represents for $H_{2} S O_{4}$

$0.50 \times V_{1} = 2 \times 40.0 \times 0.05$

$V_{1} = 8.0$ mL