Question

Volume of a gas at $t^o$C is $20$ litre when temperature of gas increases by ${50}^o$C at constant pressure than volume of gas increased by $25\%$ than calculate value of it?

Answer 1

Given: $V_1=20L$

$T_1=t^{o}C$

$V_2=(\frac{25}{100}\times 20)+V_1$

$=5L+20L=25L$

$T_2=t+50$

$V\propto T$

$\Rightarrow \frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\Rightarrow \frac{20}{t}=\frac{25}{t+50}$

$\Rightarrow 4(t+50)=5t$

$\Rightarrow {200}^{o}C=t$