Volume of air that will be expelled from a vessel of 300 cm 3 when it is heated from 27- C to 37- C at the same pressure will beA- 310 cm 3B- 290 cm 3C- 37 cm 3D- 10 cm 3

The correct option is A 310 cm3 V_2/V_1 = T_2/T_1 V_2 = T_2/T_1, V_1 = 310 K/300 K × 300 cm^3 = 310 cm^3 ...

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Byju's Answer

Standard X

Chemistry

Volume of Gases and Number of Moles

Volume of air...

Question

Volume of air that will be expelled from a vessel of 300 ${c m}^{3}$ when it is heated from $27^{o} C$ to $37^{o} C$ at the same pressure will be

310 cm³

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290 cm³

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10 cm³

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37 cm³

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Solution

The correct option is A
310 cm³

$\frac{V_{2}}{V_{1}}$ = $\frac{T_{2}}{T_{1}}$

$V_{2}$ = $\frac{T_{2}}{T_{1}}$ , $V_{1}$ = $\frac{310 K}{300 K}$ $\times$ 300 ${c m}^{3}$ = 310 ${c m}^{3}$

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Volume of air that will be expelled from a vessel of 300 cm3 when it is heated from 27o C to 37o C at the same pressure will be

The correct option is A 310 cm3 V2V1 = T2T1 V2 = T2T1, V1 = 310K300K × 300 cm3 = 310 cm3

Volume of air that will be expelled from a vessel of 300 ${c m}^{3}$ when it is heated from $27^{o} C$ to $37^{o} C$ at the same pressure will be

The correct option is A
310 cm³

$\frac{V_{2}}{V_{1}}$ = $\frac{T_{2}}{T_{1}}$

$V_{2}$ = $\frac{T_{2}}{T_{1}}$ , $V_{1}$ = $\frac{310 K}{300 K}$ $\times$ 300 ${c m}^{3}$ = 310 ${c m}^{3}$