Volume of an ideal gas is to be decreased by 10% by increase of pressure by x% under isothermal condition. Thus, x is
A
9100
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B
1009
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C
10
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D
110
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Solution
The correct option is B1009 By Boyle's law P1V1=P2V2 [∵ under isothermal condition, temperature remain constant] Final pressure is increased by x% of initial value Thus, P2=(P1+xP1100) Final volume is decreased by 10% of initial value Thus, V2=(V1−10V1100) ∴P1V1=(P1+xP1100)(V1−10V1100) =P1(1+0.01x)V1(1−0.1) 1=(1+0.01x)(0.9) ∴x=(10.9−1)0.01 ⇒x=1009