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Question

Volume of an ideal gas is to be decreased by 10% by increase of pressure by x% under isothermal condition. Thus, x is

A
9100
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B
1009
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C
10
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D
110
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Solution

The correct option is B 1009
By Boyle's law
P1V1=P2V2
[ under isothermal condition, temperature remain constant]
Final pressure is increased by x% of initial value
Thus, P2=(P1+xP1100)
Final volume is decreased by 10% of initial value
Thus, V2=(V110V1100)
P1V1=(P1+xP1100)(V110V1100)
=P1(1+0.01x)V1(10.1)
1=(1+0.01x)(0.9)
x=(10.91)0.01
x=1009

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