Volume of gas at STP is 1.12×10−7cc. Calculate the number of a molecule in it.
A
3.01×1020
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.01×1012
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3.01×1023
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.01×1024
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B3.01×1012 At STP, mole of gas occupies 22400cc. mole of gas occupies 1.12×10−7cc =1.12×10−722400×1=5×10−12moles 1 mole of any gas contains =6.022×1023molecules 5×10−12moles contains =5×10−12×6.022×1023molecules =3.011×1012molecule