Volume of one gram equivalent of $H_{2}$ at NTP is :

5.6

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11.2

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22.4

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44.8

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Solution

The correct option is B $11.2$ L
Volume of 1 mole of $H_{2}$ gas is 22.4 Litres at NTP
(1 mole of $H_{2}$ gas is 2 grams ).
So Volume of 1 gram equivalent of $H_{2}$ gas at NTP =22.4/2=11.2 Litres.

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