Volume of parallelepiped formed by vectors a-b- b-c- and c-a- is 36 sq- units-

A: [a⃗×b⃗ nbsp;b⃗×c⃗ nbsp;c⃗×a⃗] = 36 or [a⃗ nbsp; nbsp; nbsp;b⃗ nbsp; nbsp; nbsp;c⃗] = 6 B: ⇒ Volume of tetrahedron formed by v ...

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Standard XII

Physics

Vector Addition

Volume of par...

Question

Volume of parallelepiped formed by vectors $\to a \times \to b, \to b \times \to c$ and $\to c \times \to a$ is 36 sq. units.

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Solution

A: $[\to a \times \to b \to b \times \to c \to c \times \to a] = 36$
or $[\to a \to b \to c] = 6$
B:
$\Rightarrow$ Volume of tetrahedron formed by vectors
$\to a, \to b$ and $\to c$ is $\frac{1}{6} [\to a \to b \to c] = 1$
C:
$[\to a + \to b \to b + \to c \to c + \to a] = 2 [\to a \to b \to c] = 12$
D:
$\to a - \to b, \to b - \to c$ and $\to c - \to a$ are coplanar
$\Rightarrow [\to a - \to b \to b - \to c \to c - \to a] = 0$

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Volume of parallelepiped formed by vectors →a×→b,→b×→c and →c×→a is 36 sq. units.

A: [→a×→b→b×→c→c×→a]=36or [→a→b→c]=6B:⇒ Volume of tetrahedron formed by vectors→a,→b and →c is 16[→a→b→c]=1C:[→a+→b→b+→c→c+→a]=2[→a→b→c]=12D:→a−→b,→b−→c and →c−→a are coplanar⇒[→a−→b→b−→c→c−→a]=0

Volume of parallelepiped formed by vectors $\to a \times \to b, \to b \times \to c$ and $\to c \times \to a$ is 36 sq. units.