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Stoichiometric Calculations

Volume of pur...

Question

Volume of pure water is 62 $m^{3}$ and mass is 62000 kg, its density is

100 kg m

^{- 3}

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10 kg m

^{- 3}

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1000 kg m

^{- 3}

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1 x 10

^{- 3}

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Solution

The correct option is D 1000 kg m $^{- 3}$
Density $ρ = \frac{M}{V} = \frac{62000}{62} = 1000$ $k g / m^{3}$

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