Volume of the parallelopiped having vertices at O≡(0,0,0),A≡(2,−2,1),B≡(5,−4,4), and C=(1,−2,4) is
A
5cu unit
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B
10 cu unit
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C
15cu unit
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D
20cu unit
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Solution
The correct option is B10 cu unit Given, →OA=2^i−2^j−^k →OB=5^i−4^j+4^k and →OC=^i−2^j+4^k Volume of parallelopiped =[→OA→OB→OC] =∣∣
∣∣2−215−441−24∣∣
∣∣ =2(−16+8)+2(20−4)+1(−10+4) =10 cu unit.