Question

Volume of water required to convert 100ml of $0.1M{K}_{2}C{r}_2{O}_7/H^{+}$ to $0.1N$ is:

• A. $100ml$
• B. $500ml$
• C. $400ml$
• D. $200ml$

Answer 1

Answer: (B)

$500ml$

Let the volume required be x ml.
Now, normality $=$ molarity $\times$ valence factor
Valence factor of $K_{2}C{r}_2{O}_7/H^{+}=6$

Now, resulting molarity $=\frac{0.1\times 100}{100+x}=\frac{10}{100+x}$

Resulting normality $=\frac{10}{100+x}\times 6$
$0.1=\frac{60}{(100+x)}\Rightarrow 0.1x=50\Rightarrow x=500ml$